Question

At what value of `x` does the graph of `F(x) = (4x)/(3x-6)` have a vertical asymptote?

Answer 1

`"vertical asymptote at "x=2`

Explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote.

`"solve "3x-6=0rArrx=2" is the asymptote"`
graph{(4x)/(3x-6) [-10, 10, -5, 5]}