# BaCO_3 + C(s) + H_2O(l) -> CO(g) + Ba(OH)_2. If 394 g of BaCO_3 are reacted with excess carbon and water, what mass of Ba(OH)_2 should be produced?

Mar 5, 2017

You should expect 342.6 g of $B a {\left(O H\right)}_{2}$

#### Explanation:

$394 g o f B a C {O}_{3}$ is 2.00 moles.

$\frac{394 g}{197.3 \left(\frac{g}{\text{mol}}\right)} = 2.00$ mol

Looking at the equation, you see that the coefficient of both $B a C {O}_{3}$ and $B a {\left(O H\right)}_{2}$ is a one. So, the amount of $B a {\left(O H\right)}_{2}$ produced will be equal to the amount of $B a C {O}_{3}$ reacted.

2.00 " mol " Ba(OH)_2 xx 171.3 (g/"mol") = 342.6 g