Between what two consecutive integers do root3(60) lie?

Apr 8, 2018

3 and 4

Explanation:

Let's find the perfect cubes that are closest to 60

${3}^{3} = 27$

${4}^{3} = 64$

$\sqrt[3]{27} = 3$

$\sqrt[3]{64} = 4$

$\sqrt[3]{60}$ is between $\sqrt[3]{27}$ and $\sqrt[3]{64}$. Therefore it is between 3 and 4