Question

Between what two consecutive integers do `sqrt250` lie?

Answer 1

Between `15` and `16`

Explanation:

`15^2 = 225 < 250 < 256 = 16^2`

So

`15 = sqrt(225) < sqrt(250) < sqrt(256) = 16`

In fact

`sqrt(250) = [15; bar(1,4,3,3,4,1,30)]`

`= 15+1/(1+1/(4+1/(3+1/(3+1/(4+1/(1+1/(30+...)))))))`

`~~ 15.8113883`