# Between which two consecutive integers does sqrt98 lie?

Mar 28, 2018

$9 < \sqrt{98} < 10$

#### Explanation:

#sqrt98 is an irrational number because it does not have an exact answer, but is an infinite non-recurring decimal.

Consider the perfect squares closest to $98$

$64 \text{ "81" "100" } 121$
$\textcolor{w h i t e}{\times \times \times} \uparrow$
$\textcolor{w h i t e}{\times \times \times} 98 \text{ }$ is between $81 \mathmr{and} 100$

$\sqrt{81} \text{ "sqrt98," } \sqrt{100}$
$\text{ "9" "sqrt98" } 10$