# Between which two consecutive integers is the square root of 40?

Mar 2, 2018

$6 < \sqrt{40} < 7$

#### Explanation:

The first few square numbers are:$1 , 4 , 9 , 16 , 25 , 36 , 49 ,$

$\sqrt{1} = 1$

$\sqrt{4} = 2$

$\sqrt{9} = 3$

$\sqrt{16} = 4$

$\sqrt{25} = 5$

$\sqrt{36} = 6$
$\textcolor{w h i t e}{w w w w w w} \leftarrow \sqrt{40} \text{ }$ lies here
$\sqrt{49} = 7$

Therefore $\sqrt{40}$ is between $6 \mathmr{and} 7$