Brianna is graphing the function #f(x) = x^2+6x +5#. What x-intercepts should Brianna use to graph #f(x)#?

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Answer 1 · 2018-02-01T02:56:08

#(-1,0)# and #(-5,0)#

We use the fact that when a function intersects with the #x#-axis, the #y# value is equal to zero.

Since #f(x)=x^2+6x+5#, we can say that:
#y=x^2+6x+5#

When the graph of this function intersects with the #x#-axis, then #y=0#.

Therefore, we have:

#0=x^2+6x+5# We can now solve for #x#.

=>#0=(x+1)(x+5)#

#-1=x=-5#

This means that the #x#-intercepts are: #(-1,0)# and #(-5,0)#