C(-10, -16); r = 2 what is the equation?

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Answer 1 · 2018-02-22T14:48:12

#\text{Standard form:}#

#(x +10)^2 + (y +16)^2 = 4#

#\text{General form:}#

#x^2+y^2+20x+32y+356=0#

The standard form of the equation of circle is given as;

#(x – h)^2 + (y – k)^2 = r^2#

where, #(h\ , \,k)# represents the point at which the center of the circle lies and #r# represents the radius.
# #
# #
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For the center at #(h\ , \ k)=(-10\ ,\ -16)# and radius #r=2#, we have the equation in standard form of circle as:

#(x – (-10))^2 + (y –(-16))^2 = (2)^2#

Simplify to get:

#(x +10)^2 + (y +16)^2 = 4#

Expand, the expression if you want to change it into general form.

#x^2+20x+y^2+32y+356=0#