#C_6H_12O_6(s) + 6O_2(g) = 6CO_2(g) + 6H_2O(l)#. What compounds are the reactants? What compounds are the products? What is indicated by the (s), (g) and (l) in the equation?

1 Answer
anor277
Jan 25, 2017

The products are on the #"right hand side..........."#

Explanation:

And the reactants are the left hand side as written.

#(s)#, #(l)#, #(g)# represents the standard states of the reactants/products under standard condtions: i.e. #"solid; liquid; or gas"#.

#"Reactants "rarr" Products"#

The given reaction represents respiration, i.e. the combustion of glucose with dioxygen to give carbon dioxide, and water, and ENERGY. Your body chemistry is performing this now.

The reverse reaction represents another well known biological reaction. Can you name it?

#6CO_2(g) + 6H_2O(l) + Deltararr C_6H_12O_6(aq) + 6O_2(g)#

What does #Delta# represent in the equation? And how is this supplied?

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