C) Water with a density of 1040 kg/m3 flows through a horizontal pipe having a diameter of 0.4m, with a velocity of 3.2 m/s. Calculate the volumetric flow rate.?

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Answer 1 · 2018-07-08T08:05:53

The volumetric flow rate is #=0.402m^3s^-1#

The diameter of the pipe is #d=0.4m#

The cross section area of the pipe is

#A=pid^2/4=pi*(0.4)^2/4=0.126m^2#

The velocity of water in the pipe is

#v=3.2ms^-1#

The volumetric flow rate is

#q_v=Av=0.126*3.2=0.402m^3s^-1#

The density of water is

#rho=1040kgm^-3#

The mass flow rate ie

#q_m=q_v*rho=0.402*1040=418.21kgs^-1#