# C3H8(g)+5O2(g)→ 3CO2(g)+4H2O(l) (a) In the complete combustion of propane, how many moles of CO2(g) are produced per mole of O2(g)? (b) In the complete combustion of propane, how many moles of H2O(l) are produced per mole of O2(g)?

Apr 17, 2018

a) $\frac{3}{5}$
b) $\frac{4}{5}$
a) Using the mole ratio from the equation, $5$ mols of ${\text{O}}_{2}$ will produce $3$ mols of ${\text{CO}}_{2}$. Therefore, the ratio of ${\text{O}}_{2}$ used to ${\text{CO}}_{2}$ produced will be $1 : \frac{3}{5}$.
b) The same concept as in the previous question. $5$ mols of ${\text{O}}_{2}$ will produce $4$ mols of $\text{H"_2"O}$. Therefore, the ratio of ${\text{O}}_{2}$ used to $\text{H"_2"O}$ produced is $1 : \frac{4}{5}$.