Calculate #f(2)#, knowing that with any #x≠0# the correct equality #f(x)+3f(1x)=x^2# ??

1 Answer
Oct 1, 2017

The answer is #f(2)=1#.

Explanation:

First and foremost, it is imperative to note that #f(1x)=f(x)#. With this in mind, #f(x)+3f(x)=x^2# can be simplified as follows:
#f(x)+3f(x)=x^2#
#4f(x)=x^2#
#f(x)=(x^2)/4#

From here, substitute 2 wherever you have x:
#f(2)=(2)^2/4=1#.