# Calculate how many grams of the product form when 16.7 g of calcium metal completely reacts. Assume that there is more than enough of the chlorine gas? Ca(s) + Cl2(g) → CaCl2(s) please help me ...

Jun 21, 2018

You will get 46.2 g of calcium chloride.

#### Explanation:

You know that you will need a balanced chemical equation with masses, moles, and molar masses, etc.

Step 1. Assemble all the information in one place

${M}_{\textrm{r}} : \textcolor{w h i t e}{m l} 40.08 \textcolor{w h i t e}{m m m m} 110.98$
$\textcolor{w h i t e}{m m m m} {\text{Ca" + "Cl"_2 → "CaCl}}_{2}$
$m \text{/g} : \textcolor{w h i t e}{m} 16.7$

Step 2. Calculate the moles of $\text{Ca}$

$\text{Moles of Ca" = 16.7 color(red)(cancel(color(black)("g Ca"))) × ("1 mol Ca")/(40.08 color(red)(cancel(color(black)("g Ca")))) = "0.4167 mol Ca}$

Step 3 Calculate the moles of ${\text{CaCl}}_{2}$

${\text{Moles of CaCl"_2 = 0.4167 color(red)(cancel(color(black)("mol Ca")))× ("1 mol CaCl"_2)/(1 color(red)(cancel(color(black)("mol Ca")))) = "0.4167 mol CaCl}}_{2}$

Step 4. Calculate the mass of ${\text{CaCl}}_{2}$

${\text{Mass of CaCl"_2 = 0.4167 color(red)(cancel(color(black)("mol CaCl"_2))) × "110.98 g CaCl"_2/(1 color(red)(cancel(color(black)("mol CaCl"_2)))) = "46.2 g CaCl}}_{2}$