Calculate the energy of an electron in the hydrogen atom when n=2, then calculate the frequency required to ionize it?

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Answer 1 · 2018-03-21T17:53:37

#-"3.40 eV"# and #8.22 × 10^14\ "Hz"#

Energy of an electron in #"n"^"th"# orbit is

#"E" = -13.6/"n"^2\ "eV"#

#"E"_2 = -13.6/2^2\ "eV" = -"3.40 eV"#

Frequency and energy are related as

#"E" = hf#

#f = "E"_2/h = (3.40 cancel"eV" × 1.602 × 10^-19\ "J"/cancel"eV")/(6.626 × 10^-34\ "J s")#

#f = 8.22 × 10^14\ "Hz"#