Calculate the molarity of a solution prepared by dissolving 5.850g of solid NaCl in enough water to make 200mL of the solution?

Do not understand the setup.

1 Answer
Mar 21, 2018

# #
Molarity of solution #= 0.5\ M#
# #

Explanation:

# #

#\text{Molarity} = \text{Moles of solute}/\text{Volume of solution in litres}#

Solute is #\ \ \text{NaCl}#.

Molar mass of #\ \ \text{NaCl}# #= 23 + 35.5#

#= 58.5\ g# /#mol#

# #

#\text{Number of moles} = \text{Given mass}/\text{Molar mass}#

Given mass of #\ \ \text{NaCl}# #=5.85\ g#

Moles of #\ \ \text{NaCl}# #= 5.85/58.5#

#=0.1#

Volume of solution #= 200\ mL = 0.2\ L#

# #

Molarity of solution #=0.1/0.2#

#= 0.5\ M#