Calculate the molarity of a solution prepared by dissolving 5.850g of solid NaCl in enough water to make 200mL of the solution?

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Answer 1 · 2018-03-21T07:17:54

Molarity of solution $= 0.5\ M$

$\text{Molarity} = \text{Moles of solute}/\text{Volume of solution in litres}$

Solute is $\ \ \text{NaCl}$ .

Molar mass of $\ \ \text{NaCl}$ $= 23 + 35.5$

$= 58.5\ g$ / $mol$

$\text{Number of moles} = \text{Given mass}/\text{Molar mass}$

Given mass of $\ \ \text{NaCl}$ $=5.85\ g$

Moles of $\ \ \text{NaCl}$ $= 5.85/58.5$

$=0.1$

Volume of solution $= 200\ mL = 0.2\ L$

Molarity of solution $=0.1/0.2$

$= 0.5\ M$