Question

Calculate the molarity of the solution prepared by dissolving 9.8 moles of solid NaOH in enough water to make 3.62 L of solution?

Answer 1

Approx. `3*mol*L^-1`....

Explanation:

We take the quotient....`"moles of solute"/"volume of solution"`

`"Concentration"=(9.8*mol)/(3.62*L)=2.71*mol*L^-1`...