Calculate the molefraction of glucose (c6 h2 06) in a solution containing 20 percentage glucose by mass?

1 Answer
Junaid Mirza
May 13, 2018

#0.024#

Explanation:

Suppose we have #"100 g"# solution. Then in the solution there is #"20 g"# glucose and #"80 g"# water.

  • Moles of glucose#= "20 g"/"180 g/mol" = 1/9\ "mol"#
  • Moles of water#= "80 g"/"18 g/mol" = 40/9\ "mol"#

Total moles#= 1/9\ "mol" + 40/9\ "mol" = 41/9\ "mol"#

Mole fraction of glucose#= (1/9 cancel"mol")/(41/9 cancel"mol") = 0.024#

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