Calculate the moment of inertia of a wheel about its axis which having a rim of mass 24M and twenty-four spokes each of mass M and length l?

1 Answer
Jane
Jan 18, 2018

# 8 Ml^2#

Explanation:

Moment of inertia of a wheel #(I)# w.r.t an axis passing through its centre perpendicular to its plane,having mass distribution like a ring = #24 M*(l/2)^2# or #6Ml^2 #

Now 24 rods of mass #M# and length #l# will have a moment of inertia#(I')# of #((Ml^2)/12)*24# w.r.t to an axis passing through its centre and perpendicular to its plane.

Hence total moment of inertia of the system is #I+I'# = #8Ml^2#

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