Question

Calculate the number of sodium in 3.29 grams of sodium nitride ?

Answer 1

`"Number of sodium ions"~=3.0xx10^22`

Explanation:

We (i) calculate the molar quantity of `"sodium azide,"` `-=Na^+N_3^(-)` `65.01*g*mol^-1`...and so...

`"Moles of sodium azide"=(3.29*g)/(65.01*g*mol^-1)=0.05061*mol`

And so we got ……….

`0.05061*mol*"sodium atoms"xx6.022xx10^23*mol^-1`

`-=??*"sodium atoms..."`