Question

Calculate the number of sodium ions and chlorine ions and total number of ions in 14.5g of NaCl ?

Answer 1

Here is what I get:

Explanation:

14.5g of `NaCl` is equal to 0.248 mol according to the equation

`n=m/M`

Now, this equates to `1.495 times 10^23` Sodium chloride molecules.

We get this if we multiply 0.248 mol with Avogadro's number, `6.022 times 10^23`

Each molecule of Sodium chroride holds two atomic ions bonded in an ionic bond- `Na^+` and `Cl^-` in a 1:1 ratio. This means that the amount of molecules correspond with each of the individual ions.

So :
Number of Sodium ions=Number of Chloride ions= `1.495 times 10^23` ions

So the total amount of ions is twice this number, `2.990 times 10^23` ions in total.