Calculate the number of sodium ions and chlorine ions and total number of ions in 14.5g of NaCl ?

1 Answer
Mar 26, 2018

Answer:

Here is what I get:

Explanation:

14.5g of #NaCl# is equal to 0.248 mol according to the equation

#n=m/M#

Now, this equates to #1.495 times 10^23# Sodium chloride molecules.

We get this if we multiply 0.248 mol with Avogadro's number, #6.022 times 10^23#

Each molecule of Sodium chroride holds two atomic ions bonded in an ionic bond- #Na^+# and #Cl^-# in a 1:1 ratio. This means that the amount of molecules correspond with each of the individual ions.

So :
Number of Sodium ions=Number of Chloride ions= #1.495 times 10^23# ions

So the total amount of ions is twice this number, #2.990 times 10^23# ions in total.