Calculate the tensile stress in a nylon fishing line of diameter 0.36 mm which a fish is pulling with a force of 20 N?

1 Answer
May 14, 2018

5 GPa

Explanation:

Stress = F/A

Find Area of the nylon fishing line using A=pir^2 and half the diameter to get the radius and make sure you convert mm into m (*10^-3):

A=pi*((0.36*10^-3)/2)^2
A= 1.01787602*10^-7 m^2

Substitute this value into stress equation:

Stress = (1.01787602*10^-7)/20
Stress = 5*10^-9 Pa
Stress = 5 GPa