Calculate the wavelength of Radio 4 which broadcasts on a frequency of "198 kHz" ?

1 Answer
Jul 3, 2018

1.51 * 10^3 \ "m"

Explanation:

The thing to remember about wavelength and frequency is that they have an inverse relationship given by the equation

color(blue)(ul(color(black)(lamda * nu = c))

Here

  • lamda is the wavelength of the wave
  • nu is its frequency
  • c is the speed of light, usually taken to be in a vacuum, i.e. c = 3 * 10^8 \ "m s"^(-1)

This basically tells you that if you multiply the wavelength and the frequency, you must always end up with the value of the speed of light,

http://www.arpansa.gov.au/radiationprotection/basics/ion_nonion.cfm

In your case, you already know the frequency of the radio waves

"198 kHz" = 198 color(red)(cancel(color(black)("kHz"))) * (10^3 \ "Hz")/(1color(red)(cancel(color(black)("kHz")))) = 1.98 * 10^5 \ "Hz"

As you know, you have

"1 Hz" = "1 s"^(-1)

which means that the frequency of the radio waves can be written as

1.98 * 10^5 \ "Hz" = 1.98 * 10^5 \ "s"^(-1)

Since no information was given about the value of the speed of light, you can assume that you're working with the approximation

c = 3 * 10^8 \ "m s"^(-1)

Rearrange the equation to solve for lamda

lamda * nu = c implies lamda = c/nu

Plug in your values to find

lamda = (3 * 10^8 \ "m"color(red)(cancel(color(black)("s"^(-1)))))/(1.98 * 10^5 color(red)(cancel(color(black)("s"^(-1))))) = color(darkgreen)(ul(color(black)(1.51 * 10^3 \ "m")))

The answer is rounded to three sig figs, the number of sig figs you have for the frequency of the radio waves.