Question

Calculate the weight of the specific element: Barium in 5 mmol of barium sulphate (BaSO^4)?

Answer 1

Well you have a `5xx10^-3*mol` quantity of the barium salt.....

Explanation:

And as such you gots a `5xx10^-3*mol` quantity with respect to barium, a `5xx10^-3*mol` quantity of sulfur, and a `20xx10^-3*mol` quantity of oxygen. Do you agree?

And barium has a molar mass of `137.33*g*mol^-1`. How did I know this?

And thus `"mass of barium"="moles"xx"molar mass"`

`137.33*g*cancel(mol^-1)xx5xx10^-3*cancel(mol)=??*g`