Calculus of ? F=e^x÷4

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Answer 1 · 2018-05-03T02:46:51

#int e^(x/4) dx = 4e^(x/4) +C#

From the notes below I understand this question to be asking for
the solution to the integral:

#I = int e^(x/4) dx #

Let #u = x/4 -> dx = 4 du#

Hence, #I= int 4 e^u du#

#= 4 int e^u du#

#= 4 e^u +C#

Undo substitution.

#I= 4e^(x/4) +C#