Can anybody how solve this trigonometry problem???

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Answer 1 · 2018-03-14T07:25:44

#angle B = 50^0#
#c approx 18.669#
#b approx 14.301#

First we need to assume that #angle C# is a right angle.

(1)

#angle B = 180^o - (40^o + 90^o)#

#= 180^o - 130^o = 50^o#

(2)

#sin 40^o = 12/c#

#c= 12/(sin 40^o)#

#approx 12/0.642788#

#approx 18.669#

(3)

#b^2 approx 18.669^2 - 12^2#

#approx 348.5198 -144#

#approx 204.5198#

#:. b approx sqrt(204.5198)#

#approx 14.301#