Question

Can somebody solve in C?

`(ix-5)(6+2ix)(5-2i)=0`

Answer 1

A product is equal to `0` if and only if at least one of the factors is `0`. The left side is already factored for us.

Explanation:

Solve `(ix-5)=0` or `(6+2ix) = 0` (It is clear that `(5-2i)` cannot be `0`)

`x = 5/i = -5i` or `x = (-6)/(2i) = (-3)/i = 3i`

Check the answers by substitution.