# Cavin shoots an arrow at 30.0° above the horizontal. Its velocity is 49 m/s, and it hits the target. What is the maximum height the arrow will attain?

$30.62 \text{m}$
${v}^{2} = {u}^{2} + 2 a s$
$\therefore 0 = {\left(49 \sin 30\right)}^{2} - 2 \times 9.8 \times h$
$\therefore h = \frac{600.25}{19.6} = 30.62 \text{m}$