Combining 0.265 mol of #Fe_2O_3# with excess carbon produced 14.7 g of Fe. #Fe_2O_3 + 3C -> 2Fe +3CO.# What is the actual yield of iron in moles?

1 Answer
Jan 18, 2017

Answer:

Approx. #50%#

Explanation:

You have the chemical equation, which shows that each mole of ferric oxide should yield 2 moles of iron metal:

#Fe_2O_3(s) + 3C(s) rarr 2Fe(l) + 3CO(g)#

#"Moles of iron"# #=# #(14.7*g)/(55.8*g*mol^-1)# #=# #0.263*mol#

Because stoichiometric reaction would have yielded #2xx0.265*mol# of iron metal, the yield of the reaction is just under 50%.