# Complete the nuclear equation?

## My guess is: 1. 98/44 Ru 2. 52/24 Cr Thanks

May 29, 2018

Both of your guesses are correct.

#### Explanation:

1. Decay of $\boldsymbol{\text{_45^98"Rh}}$

""_45^98"Rh" -> ""_1^0"e" + ?

Positron ($\text{_1^0"e}$) is formed in the reaction. Therefore it’s a β positive decay.

In a β positive decay proton turns into neutron. Therefore the resultant atom should have

$\text{Protons = 45 – 1 = 44}$
$\text{Neutrons = (98 – 45) + 1 = 54}$

An atom with $44$ protons is $\text{Ru}$

So, β^+ decay reaction of $\text{_45^98"Rh}$ is

""_45^98"Rh" -> ""_44^98"Ru" + ""_1^0"e" + ν

——————

2. Decay of $\boldsymbol{\text{_23^52"V}}$

""_23^52"V" -> ""_"-1"^0"e" + ?

β particle ($\text{_"-1"^0"e}$) is formed in the reaction. Therefore it’s a β negative decay.

In a β negative decay neutron turns into proton. Therefore the resultant atom should have

$\text{Protons = 23 + 1 = 24}$
$\text{Neutrons = (52 – 23) – 1 = 28}$

An atom with $24$ protons is $\text{Cr}$

So, β^- decay of $\text{_23^52"V}$ is

""_23^52"V" -> ""_24^52"Cr" + ""_"-1"^0"e" + bar ν

Note: In a β-decay (both positive and negative) mass number remains same.