Complete the nuclear equation?

Question

My guess is:
1. 98/44 Ru
2. 52/24 Cr

Thanks

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Answer 1 · 2018-05-29T22:59:50

Both of your guesses are correct.

1. Decay of $bb(""_45^98"Rh")$

$""_45^98"Rh" -> ""_1^0"e" + ?$

Positron ( $""_1^0"e"$ ) is formed in the reaction. Therefore it’s a $β$ positive decay.

In a $β$ positive decay proton turns into neutron. Therefore the resultant atom should have

$"Protons = 45 – 1 = 44"$
$"Neutrons = (98 – 45) + 1 = 54"$

An atom with $44$ protons is $"Ru"$

So, $β^+$ decay reaction of $""_45^98"Rh"$ is

$""_45^98"Rh" -> ""_44^98"Ru" + ""_1^0"e" + ν$

——————

2. Decay of $bb(""_23^52"V")$

$""_23^52"V" -> ""_"-1"^0"e" + ?$

$β$ particle ( $""_"-1"^0"e"$ ) is formed in the reaction. Therefore it’s a $β$ negative decay.

In a $β$ negative decay neutron turns into proton. Therefore the resultant atom should have

$"Protons = 23 + 1 = 24"$
$"Neutrons = (52 – 23) – 1 = 28"$

An atom with $24$ protons is $"Cr"$

So, $β^-$ decay of $""_23^52"V"$ is

$""_23^52"V" -> ""_24^52"Cr" + ""_"-1"^0"e" + bar ν$

Note: In a $β$ -decay (both positive and negative) mass number remains same.