Complete the nuclear equation?
My guess is:
1. 98/44 Ru
2. 52/24 Cr
Thanks
My guess is:
1. 98/44 Ru
2. 52/24 Cr
Thanks
1 Answer
Both of your guesses are correct.
Explanation:
1. Decay of
""_45^98"Rh" -> ""_1^0"e" + ?
Positron (
In a
"Protons = 45 – 1 = 44"
"Neutrons = (98 – 45) + 1 = 54"
An atom with
So,
""_45^98"Rh" -> ""_44^98"Ru" + ""_1^0"e" + ν ——————
2. Decay of
""_23^52"V" -> ""_"-1"^0"e" + ?
In a
"Protons = 23 + 1 = 24"
"Neutrons = (52 – 23) – 1 = 28"
An atom with
So,
""_23^52"V" -> ""_24^52"Cr" + ""_"-1"^0"e" + bar ν
Note: In a