# Consider a particle initially moving with a velocity of 5m/s starts deaccelarating at a constant rate of 2m/s*2 find the distance travelled in 2sec? Ans:2m

Oct 7, 2017

See the approach below...

#### Explanation:

We simply know the formula that
$S = u t \pm \frac{1}{2} a {t}^{2}$ [Where S$\to$distance travelled, u$\to$initial velocity, t$\to$time taken, -a$\to$retardation...,+a$\to$acceleration...

Hence we can use the formula to determine the Distance...
$S = 5 \times 2 - \frac{1}{2} \times 2 \times {2}^{2}$
$S = 6 m$

Hope it helps...
Thank you...