Consider an electromagnetic wave with a frequency of #3.0xx10^10# #Hz#. What is its wavelength? What is the energy of one photon of this light?

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Answer 1 · 2016-04-28T22:35:06

#lambda = c/f=(3.0xx10^8)/(3.0xx10^10)=10^-2# #m#

#E=hf=6.63xx10^-34xx3.0xx10^10=1.99xx10^-23# #J#

For electromagnetic radiation:

#c=flambda# where #c# is the speed of light, #f# is the frequency, #lambda# is the wavelength.

Rearranging:

#lambda = c/f=(3.0xx10^8)/(3.0xx10^10)=10^-2# #m#

The energy of a photon is given by:

#E=hf# where #h# is Planck's constant, #6.63xx10^-34# #m^2kgs^-1#

#E=hf=6.63xx10^-34xx3.0xx10^10=1.99xx10^-23# #J#