Consider the neutralization reaction between CH3COOH and Sr(OH)2. Complete and balance the neutralization reaction, name the products, and write the net ionic equation.?

1 Answer
Ernest Z.
Mar 6, 2018

Here's what I get.

Explanation:

The balanced equation

#"2CH"_3"COOH(aq)" + "Sr(OH)"_2"(aq)" → underbrace(("CH"_3"COO")_2"Sr")_color(red)("strontium acetate")"(aq)" + 2underbrace("H"_2"O")_color(red)("water")"(l)"#

The ionic equation

#"2CH"_3"COOH(aq)" + "Sr"^"2+""(aq)" + "2OH"^"-""(aq)" → "2CH"_3"COO"^"-""(aq)" + "Sr"^"2+""(aq)" + 2"H"_2"O(l)"#

The net ionic equation

To get the net ionic equation, we cancel ions that occur on both sides of the reaction arrow.

#"2CH"_3"COOH(aq)" + color(red)(cancel(color(black)("Sr"^"2+""(aq)"))) + "2OH"^"-""(aq)" → "2CH"_3"COO"^"-""(aq)" + color(red)(cancel(color(black)("Sr"^"2+""(aq)"))) + 2"H"_2"O(l)"#

#color(red)(cancel(color(black)(2)))"CH"_3"COOH(aq)" + color(red)(cancel(color(black)(2)))"OH"^"-""(aq)" → color(red)(cancel(color(black)(2)))"CH"_3"COO"^"-""(aq)" + color(red)(cancel(color(black)(2)))"H"_2"O(l)"#

The net ionic equation is

#"CH"_3"COOH(aq)" + "OH"^"-""(aq)" → "CH"_3"COO"^"-""(aq)" + "H"_2"O(l)"#

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