Convert the equation y =#-(sqrt(3)/(3))x# to polar form?

1 Answer
Mar 29, 2018

#theta=(5pi)/6+pin# where #n# is an element of all integers

Explanation:

This is my first time attempting converting from rectangular to polar, so please feel free to correct If I am wrong

The conversion from Rectangular to Polar:
#x=rcostheta#
#y=rsintheta#

And the point is solve for #theta# in this case as the #r# cancels:
1. Substitute into the Rectangular form:
#rsintheta=-sqrt3/3*rcostheta#
2. Subtract #rcostheta# from both sides:
#(rsintheta)/(rcostheta)= -sqrt3/3#
3. Recall #sintheta/costheta= tantheta#:
#tantheta= -sqrt3/3#
4. General solution
#theta=(5pi)/6+pin# where #n# is an element of all integers