Cos2A+tanA = cosec2A Prove It ??

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Answer 1 · 2018-05-20T14:51:40

#cosec2A#.

Sorry Question is #cot2A+tanA#

# cot2A+tanA#,

#=(cos2A)/(sin2A)+sinA/cosA#,

#=(cos2AcosA + sin2A sinA)/(sin2AcosA)#,

#=(cos(2A-A))/(sin2AcosA)#,

We know that, #cos2A cosA + sin2A sinA = cos(2A-A)#.

#:. cot2A+tanA=cosA/(sin2AcosA)#,

#=1/(sin2A)#,

#=cosec2A#.

Proved....