(CotA-cosecA)^2= 1-cosA/1+cosA ?

1 Answer
Hriman
Feb 24, 2018

#(CotA-cscA)^2= (1-cosA)/(1+cosA)#
#Cot^2A-2CotAcscA+csc^2x= (1-cosA)/(1+cosA)#
#Cos^2A/sin^2A-(2CosA)/sin^2A+1/sin^2A= (1-cosA)/(1+cosA)#

#(Cos^2A-2CosA +1)/sin^2A= (1-cosA)/(1+cosA)#

#(Cos^2A-2CosA +1)/(1-cos^2A)= (1-cosA)/(1+cosA)#

#((1-CosA)(1-CosA))/((1+cosA)(1-cosA))= (1-cosA)/(1+cosA)#

#(1-cosA)/(1+cosA) =(1-cosA)/(1+cosA)#

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