# Could you give me details of the answer?

Mar 31, 2018

E

#### Explanation:

$\frac{{b}^{3} \sqrt[3]{{a}^{2} {b}^{5}}}{a}$ this is what your question looks like as

Rule 1: ${a}^{-} 1 = \frac{1}{a} ^ 1 = \frac{1}{a}$

Rule 2: $\sqrt{x} = {x}^{\frac{1}{2}}$

$\frac{{b}^{2} {\left({a}^{2} {b}^{5}\right)}^{\frac{1}{3}}}{a}$

Rule 3: $\sqrt{a b} = \sqrt{a} \sqrt{b} = {\left(a b\right)}^{\frac{1}{2}} = {a}^{\frac{1}{2}} {b}^{\frac{1}{2}}$

$\frac{{b}^{2} {a}^{\frac{2}{3}} {b}^{\frac{5}{3}}}{a}$

Rule 4: ${a}^{2} \cdot {a}^{3} = {a}^{2 + 3} = {a}^{5}$

Rule 5: ${a}^{2} / {a}^{3} = {a}^{2 - 3} = {a}^{-} 1$

${b}^{2 + \frac{5}{3}} {a}^{\frac{2}{3} - 1} = {b}^{\frac{6}{3} + \frac{5}{3}} {a}^{\frac{2}{3} - \frac{3}{3}} = {b}^{\frac{11}{3}} {a}^{- \frac{1}{3}} = {b}^{\frac{11}{3}} / {a}^{\frac{1}{3}}$