Could you please help with this trig?

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2 Answers
Dec 4, 2017

option B #costheta#

Explanation:

#cottheta/csctheta, sintheta!=0#

#cottheta/csctheta=(costheta/sintheta)/(1/sintheta)#

#=costheta/sintheta -:1/sintheta#

#=costheta/cancel(sintheta)xxcancel(sintheta)/1#

#=costheta#

Dec 5, 2017

#B#

Explanation:

#"using the "color(blue)"trigonometric identities"#

#•color(white)(x)cottheta=costheta/sintheta" and "csctheta=1/sintheta#

#rArrcottheta/csctheta#

#=(costheta/sintheta)/(1/sintheta#

#=costheta/cancel(sintheta)xxcancel(sintheta)/1#

#=costhetatoB#