Cscx/secx = cotx ?

1 Answer
Jim G.
Mar 9, 2018

#"see explanation"#

Explanation:

#"using the "color(blue)"trigonometric identities"#

#•color(white)(x)cscx=1/sinx" and "secx=1/cosx#

#•color(white)(x)cotx=cosx/sinx#

#"Consider the left side"#

#rArr(1/sinx)/(1/cosx)#

#=1/sinx xxcosx/1#

#=cosx/sinx=cotx="right side "rArr"verified"#

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