Derivative ? sin^-1 2x ,with respect to x

1 Answer
Jun 17, 2018

2/sqrt(1-4x^2)

Explanation:

Note that

(sin^-1(x))^'=1/sqrt(1-x^2)

then by the chain rule we get

f^'(x)=1/sqrt(1-(2x)^2)*(2x)^'=2/sqrt(1-4x^2)