Question

Derivative ? `sin^-1 2x` ,with respect to x

Answer 1

`2/sqrt(1-4x^2)`

Explanation:

Note that

`(sin^-1(x))^'=1/sqrt(1-x^2)`

then by the chain rule we get

`f^'(x)=1/sqrt(1-(2x)^2)*(2x)^'=2/sqrt(1-4x^2)`