Derivative of #(2+sqrt(4-(x)^2))/x# ?

1 Answer
Aug 23, 2017

#(d((2+sqrt(4-x^2))/x))/dx = -(2sqrt(4-x^2)+4)/(x^2sqrt(4-x^2))#

Explanation:

Use the product rule:

#(d(g/h))/dx = ((dg)/dxh-g((dh)/dx))/h^2#

let #g = 2+sqrt(4-x^2)#, then #(dg)/dx = -x/sqrt(4-x^2)#

This implies that #h = x# and #(dh)/dx = 1#

Substituting into the rule:

#(d((2+sqrt(4-x^2))/x))/dx = (-x^2/sqrt(4-x^2)-2-sqrt(4-x^2))/x^2#

#(d((2+sqrt(4-x^2))/x))/dx = (-x^2-2sqrt(4-x^2)-(4-x^2))/(x^2sqrt(4-x^2))#

#(d((2+sqrt(4-x^2))/x))/dx = -(2sqrt(4-x^2)+4)/(x^2sqrt(4-x^2))#