Derive the frequency for a third harmonic in a closed pipe from #f=v/lamda# ?

1 Answer
Jul 22, 2018

Answer:

#f= (3v)/(4L)#

Explanation:

Well let's see, we know that frequency is equal to:
#f=v/lamda#

We also know that the wavelength at a third harmonic in a closed pipe is:
#L=3/4lamda#

#L# is the length of the pipe

Isolate lamda:
#4/3L= lamda#

Substitute for wavelength in the first equation:
#f=v/(4/3L)#

#f= (3v)/(4L)#