Question

Determine all critical points for the function???? please help me `x^2-6x+7`

Answer 1

You'll have one 'C' value at x = 3

Explanation:

Assuming `y=x^2-6x+7`, first start by taking the first derivative.

`dy/dx = 2x - 6 + 0` `rarr` `dy/dx = 2x-6`

Next set the first derivative equal to zero, as you'll find critical points when `dy/dx=0 or dy/dx= DNE`

`2x - 6 = 0 rarr 2x = 6 rarr x = 3`

Solving the first derivative for when it is 0 yields a x value of 3 or in this case a 'C' value (critical point).