Question

Determine the molarity and nomality of the aqueous solution containing 100g of Al2(SO4)2?

Answer 1

`"Molarity"="Moles of solute"/"Volume of solution"`

Explanation:

Now `"moles of solute"=(100*g)/(342.15*g*mol^-1)=??*mol`

But we ain't got a volume of solvent specified........so we cannot proceed......

And by the way `"aluminum sulfate"` is `Al_2(SO_4)_3`, the salt of `Al^(3+)` and `SO_4^(2-)` ions..........