Then teach the underlying concepts
Don't copy without citing sources
preview
?

#### Explanation

Explain in detail...

#### Explanation:

I want someone to double check my answer

2
Mar 8, 2018

See below.

#### Explanation:

Imposing a vertical acceleration on ${m}_{A}$ as a consequence, due to kinematic restrictions, we have

${a}_{2}^{2} = {a}_{x}^{2} + {a}_{1}^{2}$

with

${a}_{1} / {a}_{x} = \tan \theta$

hence

${a}_{2}^{2} = {a}_{1}^{2} / {\sin}^{2} \left(\theta\right)$

Then teach the underlying concepts
Don't copy without citing sources
preview
?

#### Explanation

Explain in detail...

#### Explanation:

I want someone to double check my answer

1
ashu Share
Mar 7, 2018

The relation between accelerations is that a1 is
2 times of a2.The steps are following.

#### Explanation:

As a1 is acting vertically we can say it is equal to mg.
=> a1 = mg. .......(1)
Mg is acting vertically downwards the componentof it along a2 will be equal to it.
=>a2=mgsin30. .....(2)
=>a2=mg (1/2) [as sin30=1/2]
=>a2=mg/2
=>2(a2)=mg .......(3)
By analyzing equation (1) and (3) we get that both are equal.
So,
=> 2(a2)=mg= a1

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