Determine the temperature of a 25.0g sample of neon gas that exerts a pressure of 0.922 atm and has a volume of 3.25L?

1 Answer
anor277
Feb 21, 2018

#T=30*K#

Explanation:

Well, we use the old Ideal Gas equation....

#T=(PV)/(nR)=(0.922*atmxx3.25*L)/((25.0*g)/(20.2*g*mol^-1)xx0.0821*(L*atm)/(K*mol))=29.5*K#...now this is very close to the normal boiling point of neon (approx. #20*K#?)...and you should note that the result may not be reliable because the assumptions of ideality are not met in the question....

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