Question

Differentiate `sinx` `/` `5x` + `sec^2 x"` ?

Answer 1

`(xcosx-sinx)/(5x^2)+2sec^2xtanx`

Explanation:

`d/dx(sinx/(5x)+sec^2x)`
`=d/dx(sinx/(5x))+d/dx(sec^2x)`
`=((d(sinx))/dx(5x)-sinx(d(5x))/dx)/(5x)^2+(d(sec^2x))/(dsecx)*(d(secx))/dx`
`=(cosx*5x-5sinx)/(25x^2)+2secx*secxtanx`