Differentiation of x-1/x+1?

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Answer 1 · 2018-05-19T03:27:40

#2/(x+1)^2#

#d/(dx) (x-1)/(x+1)#

= #((x+1)(1)-(x-1)(1))/(x+1)^2#

= #(x+1-x+1)/(x+1)^2#

= #2/(x+1)^2#

#(dy)/(dx) u/v#

= #(vu'-uv')/v^2#

So in your case:

#u=x-1# and #v=x+1#