Dimensional formula of 1/4πE0?

1 Answer
Feb 27, 2018

#ML^3T^-4I^-2#

Explanation:

Coulomb's law
#F=1/{4pi epsilon_0} {q_1q_2}/r^2#

implies

#[1/{4pi epsilon_0}] = [{Fr^2}/{q_1q_2}] = {MLT^-2L^2}/{(IT)^2} = ML^3T^-4I^-2#

Note, in the SI system current is one of the fundamental dimensions.

Also, the SI unit of #[1/{4pi epsilon_0}] #, #Nm^2C^-2 # is often written in the form #m/F# (meters per Farad)