Question

Dimensional formula of 1/4πE0?

Answer 1

`ML^3T^-4I^-2`

Explanation:

Coulomb's law
`F=1/{4pi epsilon_0} {q_1q_2}/r^2`

implies

`[1/{4pi epsilon_0}] = [{Fr^2}/{q_1q_2}] = {MLT^-2L^2}/{(IT)^2} = ML^3T^-4I^-2`

Note, in the SI system current is one of the fundamental dimensions.

Also, the SI unit of `[1/{4pi epsilon_0}]`, `Nm^2C^-2` is often written in the form `m/F` (meters per Farad)