Does #sin^2theta-cos^2theta=1-2sin^2theta#?

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Answer 1 · 2018-05-12T04:47:08

#"No"#
#"Almost :"#
#sin^2(theta) - cos^2(theta) = 2 sin^2(theta) - 1#

#sin^2(theta) + cos^2(theta) = 1#

#=> sin^2(theta) - cos^2(theta)#
#= sin^2(theta) - (1 - sin^2(theta))#
#= 2 sin^2(theta) - 1#

Answer 2 · 2018-05-12T04:49:02

No that would be equal to #2sin^2theta-1#

Since #cos^2theta=1-sin^2theta#
Putting the value #cos^2theta# in original equation we get
#2sin^2theta-1#