Question

Does someone know how to answer this question?

1. What mass of sodium oxide will be formed
   by burning 20 g of sodium in air?

Answer 1

The answer to your first question is yes....

Explanation:

As to the answer, we write the stoichiometric equation to inform our arithmetic.....

`2Na(s) + 1/2O_2(g) rarr Na_2O(s)`

This is a redox equation for which BOTH charge and mass are balanced....

And so we find the moles of sodium metal....

`"moles"_(Na)=(20*g)/(22.99*g*mol^-1)=0.870*mol`...

And given the stoichiometry of the reaction (what do I mean by this?), there is half an equiv of dioxygen gas....i.e. a mass of....

`0.870*molxx1/2xx32.00*g*mol^-1~=14*g`

And thus we get mass of approx. `34*g` with respect to `Na_2O`...